an electron in a hydrogen atom in its ground state absorbs twice is ionization energy what is the wavelength of the emitted electron
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The wavelength of the emitted electron would be the same as when it absorb the ionization energy the left out energy would be utilized in providing kinetic energy to the electron. Formula for Ionization Energy:
KE= Energy Supplied-IE=2IE-IE=IE
Where as:
Wavelength= Plank's Constant/ Momentum
KE= Energy Supplied-IE=2IE-IE=IE
Where as:
Wavelength= Plank's Constant/ Momentum
Answered by
7
Kinetic Energy(free electron)= Energy Supplied - IE = 2IE-IE = IE
(The idea is similar to Einstein’s idea of photoelectric effect)
KE= momentum*momentum/2*mass of Electron
Momentum= Sqrt(2*KE*mass of an electron)
By De Broglie's Formula, any classical object has an associated classical wavelength by:
Wavelength= Planck’s constant/ Momentum
You know momentum from 3 and Planck’s constant is a fundamental constant, hence plug and chug and you have the wavelength of the associated free electron!
(The idea is similar to Einstein’s idea of photoelectric effect)
KE= momentum*momentum/2*mass of Electron
Momentum= Sqrt(2*KE*mass of an electron)
By De Broglie's Formula, any classical object has an associated classical wavelength by:
Wavelength= Planck’s constant/ Momentum
You know momentum from 3 and Planck’s constant is a fundamental constant, hence plug and chug and you have the wavelength of the associated free electron!
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