An electron in a hydrogen atom jumps from 4th stationary state to the ground state. Find the
frequency of the radiation emitted. h = 6.6 x 10^-34 Js
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Answer:
Energy released when electron in the atom jumps from excited state (n=3) to ground state (n=1) is
E=hν=E
3
−E
1
=
3
2
−13.6
−(
1
2
−13.6
)=
9
−13.6
+13.6=12.1 eV
Therefore, stopping potential: eV
0
=hν−ϕ
0
=12.1−5.1 [∵ work function ϕ
0
=5.1]
⇒V
0
=7V
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