Question

An electron in a hydrogen atom jumps from 4th stationary state to the ground state. Find the        
      frequency of the radiation emitted.  h = 6.6 x 10^-34 Js

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Answer 1

Answer:

Energy released when electron in the atom jumps from excited state (n=3) to ground state (n=1) is

E=hν=E

3

−E

1

=

3

2

−13.6

−(

1

2

−13.6

)=

9

−13.6

+13.6=12.1 eV

Therefore, stopping potential: eV

0

=hν−ϕ

0

=12.1−5.1 [∵ work function ϕ

0

=5.1]

⇒V

0

=7V