Question

An electron in an atom jumps in such a way that its kinetic energy changes from x to x/4. Then find change in potential energy?

Answer 1

we know the change in kinetic energy is equal to change in potential energy so it is-3X/4

Answer 2

Answer: Here is your answer↓

+ 3x /2

Explanation:

change in K.E.(ΔK.E.) = K.E. final ( K.E. f )  - K.E. initial ( K.E. i )

                         Δ K.E. = X/4 -X

                                    = - 3X/4

 Now, we know that Δ K.E. = - ( Δ P.E. /2 )

                                    -3x /4 = Δ P.E. /2

                                       Δ P.E. =3X /2

Therefore ,the change in potential energy will be Δ P.E. =3X /2