Question

An electron in an atom jumps in such a way that its
kinetic energy changes from x to .x/4The change in
potential energy will be
​

Answer 1

The change in kinetic energy [KE]:-

x - x/4 = + 3x/4

Now we know that KE = mod of TE

Therefore TE = 3x/4

Now there is another formula that is:-

PE [Potential energy] = 2 TE

PE = 2 * 3x/4

PE = + 3x/2.

Answer 2

The correct answer is $\frac{3x}{2}$.

Given: Initial Kinetic energy = x.

Final Kinetic energy = $\frac{x}{4}$.

To Find: Change in potential energy.

Solution:

The change in kinetic energy is

$x-\frac{x}{4} =\frac{3x}{4}$

Now, we know that KE = |TE|  (TE = Total Energy)

Therefore,

TE = $\frac{3x}{4}$

Now as we know that,

PE [Potential energy] = 2 TE

PE = 2 *  $\frac{3x}{4}$

PE = $\frac{3x}{2}$.

Hence, the change in potential energy is  $\frac{3x}{2}$.

#SPJ3