Question

an electron in an atom n=4 is in a first energy state ionization energy of atom will be​

Answer 1

Answer:

Be - e- -> Be+¹ + 899kJ/mol

Explanation:

We know, BERYLLIUM is the element with atomic no. 4.

Therefore,

According to the question,

Beryllium has 2 valency electrons.

We know, Ionization energy means the energy required to remove an electron from its valency cell of the element.

1st Ionization energy is the energy required to remove the first electron...

Thus, the energy requied to remove 1st electron from Beryllium is 899kJ/mol