Physics, asked by devanshg7521, 14 hours ago

An electron in an atom revolves around the nucleus in an orbit of radius 0.53 angstrom. Calculate the equivalent magnetic moment if the frequency of revolution of electron is 6.8 x 10 9 MHz.

Answers

Answered by santa19
1

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Answered by sanghasheelakamble29
1

The equivalent magnetic moment is 9.6 x 10∧ -24 Am².

Given: radius of orbit = r =0.53 angstrom.

          charge of electron = q = e = 1.6 x 10 ∧-19

          Frequency of revolution of electron= f  = 6.8 x 10∧9MHz.

                                                                            = 6.8 x 10∧15 Hz.

To Find: Equivalent magnetic moment= ?

Solution :

We know the equation  for magnetic moment : M=NIA

Where, N= No. of turns =1

I= current

A= area = πr²

We know charge (q) = current (I)/Time (t)

So  I = t x q

f = 1/t

So I = f x q

Putting values in the equation, M=NIA

M= N x f x q x π x r²

  =1 x 6.8 x 10∧15  x 1.6 x 10 ∧-19 x 3.14 x (0.53 x 10 ∧-10)²

  = 9.6 x 10∧ -24 Am².

Therefore, the equivalent magnetic moment is 9.6 x 10∧ -24 Am².

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