Question

An electron in the hydrogen atom is making 6 x 10 ^15 revolutions per second. Calculate the centripetal force if the radius of the circular orbit is 0.53A. (mass of an electron =9.1 x 10^-31 kg) ( calculate it in newton)

Answer 1

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Answer 2

Answer:

Here is answer to the question.

Explanation:

Answer

We have,

f=6×1015H2​ So,

ω (angular frequency)=2πf=2n×6×1015 rad/s

Radius of revolution=0.53A˙=5.3×10−11m

We know that,

Centripetal force = rmv2​=rm(ωR)2​=ω2m2

Mass of electron = 9.1×10−31 kg, so

Centripetal force = (9.1×10−31)(2π×6×1015)2(5.3×10−11)

=6.854×10−8N

solution