Question

an electron in the potentiometer wire experiences a force of 3.2 ×10^-19 . the length of the potentiometer is 4m .the e.m.f of the battery across the wire is ​

Answer 1

Answer:

ANSWER IS................... 8 V

Explanation:

F=3.2 X 10∧-19

WE KNOW THAT........ F=qE................................1

E=V/l..........................................................................2

sub. 2 in 1......... F=qV/l

3.2 x 10∧-19 = 1.6x10∧-19 x V/4

V = 8 V.............................

Answer 2

The e.m.f of the battery across the wire is 8 volts.

Explanation:

It is given that,

Force acting on the electron, $F=3.2\times 10^{-19}\ N$

Length of the potentiometer is 4 meters. Due to the force, an electric field will be created in the wire. The electric force acting on it is given by :

$F=qE$

Also, $E=\dfrac{V}{l}$

$F=\dfrac{qV}{l}$

$F=\dfrac{qV}{l}$

$V=\dfrac{Fl}{q}$

$V=\dfrac{3.2\times 10^{-19}\times 4}{1.6\times 10^{-19}}$

V = 8 volts

So, the e.m.f of the battery across the wire is 8 volts. Hence, this is the required solution.

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