Question

An electron initially at rest falls a distance of 1.5 cm in uniform electric field of magnitude

Answer 1

Given that,

Distance

Electric field

Mass of electron

Mass of proton

Charge

Distance travelled by both particle

Now, using of equation of motion

Initial velocity u = 0 m/s

So,

.....(I)

We know that,

The electric force is

F = qE

Now, newton's second law

F = ma

Now, on equating to both force

F = qe = ma

So, ....(II)

Now, put the value of a in equation (I)

The time of fall in each case

...(III)

Now, put the value of all elements in equation (III)

For electron,

Now, for proton

Hence, this is the required solution.