Physics, asked by ajith9289, 8 months ago

An electron is accelerated by a p.d. of 1000 V. Its velocity
will be
(a) 3.78 × 10⁷ m/s (b) 1.89 × 10⁷ m/s
(c) 5.67 × 10⁷ m/s (d) 0.95 × 10⁷ m/s

Answers

Answered by gurmukhjosan
1

Answer:

b

Explanation:

we know that V=W/C

So (mv^2)÷2=1000×e

(9.1×10^-31×v^2)÷2 =1000×1.6×10^-19

0n solving the answer is b

Similar questions