An electron is accelerated by a p.d. of 1000 V. Its velocity
will be
(a) 3.78 × 10⁷ m/s (b) 1.89 × 10⁷ m/s
(c) 5.67 × 10⁷ m/s (d) 0.95 × 10⁷ m/s
Answers
Answered by
1
Answer:
b
Explanation:
we know that V=W/C
So (mv^2)÷2=1000×e
(9.1×10^-31×v^2)÷2 =1000×1.6×10^-19
0n solving the answer is b
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