Question

An electron is accelerated by a potential difference of 25 volt . Find the de- Broglie wavelength associated with it.

Answer 1

Answer:

de broglie wavelength for e^- =12.27/√v

12.27/√25

12.27/5 = 2.45

Answer 2

De Brogli wavelength = 2.449 A°  

Given:

An electron is accelerated by a potential difference of 25 volt.

To find:

The de- Broglie wavelength associated with it.

Formula used:

For an electron, de Brogli wavelength is given by,    λ=$\sqrt{\frac{150}{v} }$

Where,  V = potential difference.

Explanation:

Given that  V = potential difference = 25 volt.

From the above formula,

de Brogli wavelength is given by,     λ=$\sqrt{\frac{150}{v} }$

                                                            λ==$\sqrt{\frac{150}{25} }$

                                                           λ= $\sqrt{6}$

                                                            λ= 2.449 A°

De Brogli wavelength = 2.449 A°                

To learn more...

1)Wavelength of a particle of mass m moving with velocity v is

https://brainly.in/question/15138016