Question

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227×10−2 nm, the potential difference is :

Answer 1

Answer:

Explanation:

The de-broglie wavelength of an electron is given as:

λ= 1.227/√V nm

Substitute the wavelength in the above expression:

V=(  1.227/1.227×10 −2 ) $^{2}$

V=10 $^{4}$ V