Question

An electron is accelerated in an electric field of 40 V cm", if e/m of electron is
1.76 x 10" Ckg', the acceleration is nearly
O(A). 14.0 x 10" ms?
(B). 14.0 x 100 ms
(C). 7.0 x 100 ms
OD). 7.0 x 10 ms?​

Answer 1

Answer:

C

Explanation:

a = Fe / m = qE/m= E (q/m)  

a = 40 Vcm^-1 x 1.76x10^1 ckg^-1

a = 400 Vm^-1 x 1.76x10^1 ckg^-1

a = 7.0 x 100 ms^-2