Question

An electron is accelerated through a P.D of 182 volt . calculate its associative wave length​

Answer 1

Answer:

Using energy conservation, KE=PE or 2mp2=eV or p=2meV where p= momentum of electron, m= mass of electron, e= charge of electron and V= potential difference.

Now, de-Broglie wavelength λ=ph=2meVh=2(9.1×10−31)(1.6×10−19)(100)6.6×10−34=1.22×10−10m