Question

An electron is accelerated through a potential difference of 100 v , then de-broglie wavelength associated with it is approximately

Answer 1

Answer:

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Answer 2

The De-Broglie wavelength associated with it is 1.22 A.

Explanation:

Given that,

An electron is accelerated through a potential difference of 100 V, V = 100 volt

We know that the relation between De-Broglie wavelength and the potential difference is given by the formula as :

$\lambda=\dfrac{12.27}{\sqrt{V} }\ A\\\\\lambda=\dfrac{12.27}{\sqrt{100} }\\\\\lambda=1.22\ A$

So, the De-Broglie wavelength associated with it is 1.22 A. Hence, this is the required solution.

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De-Broglie wavelength

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