Question

An electron is accelerated through a potential difference of 500 V. Its de Broglie wavelength would be

Answer 1

h=planks const =6.6×10^-34

Mass of electron =9.1×10-31

Voltage= 500

Wavelength (w)

= h/√2mKE

= h/√2meV

=6.6×10^-34/√2×9.1×10-31×500

=6.6×10^-34/√910×10-30

=6.6×10^-34/30.1×10-15

=0.219×10-19

I hope this helps ( ╹▽╹ )