an electron is accelerated through a potential difference V. Write an expression for its final speed ,if it was initially at rest
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I'm writing this answer assuming you know basics of electrostatics.
Work done = e×V (e - charge on electron, V - potential difference)
Since this work is stored in the form of Kinetic energy ,
(0.5)mv² = e×V
Therefore v = [(2×e×V)÷m]^½
Work done = e×V (e - charge on electron, V - potential difference)
Since this work is stored in the form of Kinetic energy ,
(0.5)mv² = e×V
Therefore v = [(2×e×V)÷m]^½
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