Physics, asked by sai1410, 2 months ago

An electron is bound in one dimensonal infinite well, the first three excited state energy
values in terms of the ground state energy

Answers

Answered by skar7882
0

Explanation:

3.     An electron is bound in one-dimensional infinite well of width 1 × 10–10 m. Find the energy values in the ground state and first two excited states

Answered by AnkitaSahni
1

In a one dimensional infinite well, the first three excited state energy values in terms of the ground state energy of an electron are as follows;

If 'L' is the width of the one dimensional infinite well, then the energy of the nth excited energy state is;

E_{n} = ( n^{2}h^{2} ) / 8mL^{2} , where 'h' is the Planck's constant and 'm' is the mass of the electron.

E_{n} = (n^{2}/ L^{2}) (6.038 x 10^{-38}) J

Ground state n = 1

Ground state energy E_{1} = [(6.038 x 10^{-38}) / L^{2}]J

First excited state       E_{2} = 2^{2} E_{1} = [(2.415 x 10^{-37}) / L^{2}]J

Second excited state E_{3} = 3^{2} E_{1} = [(5.432 x 10^{-37}) / L^{2}]J

Third excited state     E_{4} = 4^{2} E_{1} = [(9.66 x 10^{-37}) / L^{2}]J    

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