Physics, asked by vanajadaliparti09, 11 months ago

An electron is confirmed to a box of length 10^8 m. Calculate the minimum uncertainty in its velocity. Given that m=9.1×10^-31 kg and h=1.05×10^-34

Answers

Answered by Faisalkhan234

0

Answer:1.75*70^-12 m/s

Explanation:

Δx*Δp=h/2Π .........p=mv

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