Question

An electron is emitted with a velocity of
5x 100 m s. It is accelerated by an electric field in
the direction of initial velocity at 3 x 1014 m. s. If its
final velocity is 7x10 m s-1, calculate the time taken by the
electron to attain the final velocity and the distance covered
by it.​

Answer 1

Hello friends.

Answer : distance, s = 0.04 m

Explanation :

It is given that,

Initial velocity of electron,

Final velocity of electron,

Acceleration of electrons,

We know from the third equation of motion :

where,

s is the displacement of the electron.

On solving,

or

Hence, the distance covered by the electron is 0.04 m.

hope it's helpful for you...

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