an electron is moving at 10^ 6 metre per second in the direction parallel to the current 5 ampere is flowing through the infinitely long straight word separated by the perpendicular distance of the 10 centimetre calculate the magnitude of the force experienced by the electron
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Answered by
56
Answer:
Explanation:
=> It is given that,
velocity, V = 10⁶ m/sec
current, I = 5 A
q_e = 1.6 * 10⁻¹⁹
perpendicular distance, d = 10 cm = 0.1 m
=> B = μ_0I/ 2πd
= 4π * 10⁻⁷ * 5 / 2π * 0.1
= 10⁻⁵ T
=> Magnitude of force = q_e * V * B
= 1.6 * 10⁻¹⁹ * 10⁻⁵ * 10⁶
= 1.6 * 10⁻¹⁸N
Thus, the magnitude of the force experienced by the electron is 1.6 * 10⁻¹⁸
Answered by
10
=> It is given that,
velocity, V = 10⁶ m/sec
current, I = 5 A
q_e = 1.6 * 10⁻¹⁹
perpendicular distance, d = 10 cm = 0.1 m
=> B = μ_0I/ 2πd
= 4π * 10⁻⁷ * 5 / 2π * 0.1
= 10⁻⁵ T
=> Magnitude of force = q_e * V * B
= 1.6 * 10⁻¹⁹ * 10⁻⁵ * 10⁶
= 1.6 * 10⁻¹⁸N
Thus, the magnitude of the force experienced by the electron is 1.6 * 10⁻¹⁸
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