Chemistry, asked by jinnapupavankumar, 9 months ago

An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 x 10-2 T. If the value of e/m is 1.76 x 1011 C/kg, the frequency of revolution of the electron is

Option 1) 
1 GHz

 

Option 2) 
100 MHz

 

Option 3) 
62.8 MHz

 

Option 4) 
6.28 MHz​

Answers

Answered by sowsriakansha12345
2

Answer:

the answer is 2 the correct option

Answered by shrutikumari180802
1

Answer: 1GHz

Explanation:

f=qB/2πm = 1.76*10¹¹*3.57*10^-2/2*3.14 = 10^9 = 1GHz

Similar questions