An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 x 10-2 T. If the value of e/m is 1.76 x 1011 C/kg, the frequency of revolution of the electron is
Option 1)
1 GHz
Option 2)
100 MHz
Option 3)
62.8 MHz
Option 4)
6.28 MHz
Answers
Answered by
2
Answer:
the answer is 2 the correct option
Answered by
1
Answer: 1GHz
Explanation:
f=qB/2πm = 1.76*10¹¹*3.57*10^-2/2*3.14 = 10^9 = 1GHz
Similar questions