Question

An electron is moving in Bohr's fourth orbit it's debroglie wavelength is lambda then circumference of fourth
orbit is?

Answer 1

Hi friend here is your answer.

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We know

n×lamda=2×pi×r

So n=4

2×pi×r=4×lamda

ans.

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Answer 2

Answer:

Explanation:

Circumference =2pir=2pi×2lambda/pi. = then pi and pi is cut and correct answer is 4lambda.