Question

An electron is moving in circular orbital of radius 10 cm in a uniform magnetic field B=0.5 T. What is the period of revolution T of the electron?
Select one:
12 ps
32 ps
71 ps
60 ps

Answer 1

Answer:

hey mate

Explanation:

Solution :

(a) R = 1 m, B = 0.5 T, R = mu/qB

rArr v = 0.0879 xx 10^(10)

= 8.79 xx 10^(10)

= 8.8 xx 10^(10)m/s

(b) r = mu/ qB

rArr v = (qBr)/(m)= 0.5 xx 10 ^(8)

= 5 xx 10^(7) m/s