Question

an electron is moving on the third bohr Orbit calculate the energy of the electron given the energy of the first bohr orbit is 13.6 electron volt

Answer 1

Answer:1.51 eV

Explanation:

E = 13.6 × z^2 / n^2

Given that E in the first shell is 13.6 eV

Therefore it is evident that z(atomic number ) is 1

Therefore ,

E(3) = 13.6 /9

=1.51 eV

Answer 2

The energy of the electron  moving on the third bohr Orbit is 1.51 eV

Explanation:

Energy of the nth orbit by Bohr was given by:

$E_n=R_H\times \frac{Z^2}{n^2}eV$

where,

$E_n$ = energy of n^{th} orbit

$R_H$ = Rydberg constant

n = number of orbit  = 3

Z = atomic number = 1 (for hydrogen)

Energy of the first shell(n=1) in hydrogen atom:

Z = 1

$13.6eV=R_H\times \frac{1^2}{1^2}$

$R_H=13.6eV$

To find energy value of electron in the 3rd orbit

$E_n=13.6\times \frac{1^2}{3^2}eV=1.51eV$

The energy of the electron  moving on the third bohr Orbit is 1.51 eV

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