Question

An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The coulomb force between the two is?

Answer 1

Answer:

ke^2/r^3-r (bar)

Explanation:

F(vector)= kq1q2/mod of r^3× r(vector)

= ke(-e)/mod of r^3×r(vector)

= -ke^2/r^3-r(vector)

NOTE:

i put words in place of some symbols as i wasnt having them in my keyboard. sorry for the inconveniences if any....

hope it helped...☺☺

now plz help me by thanking and following....

Answer 2

Answer:

Explanation:Using Coulomb's law, the force between two charges is given by,

F

=k

r

3

q

1

​

q

2

​

​

r

where r= distance between charges.

Here, q

1

​

=−e, charge of an electron ; q

2

​

=Ze=e, charge of the nucleus and r= radius of hydrogen atom.

(note: for a hydrogen atom, atomic number =Z=1)

Thus, the force between electron and nucleus will be, F=k

r

3

(−e)e

​

r

=−k

r

3

e

2

​

r