Question

An electron is moving vertically upward in the uniform magnetic field of the earth. The

velocity of the electron is 2 x 10^6 m/s and the horizontal component of earth’s magnetic field

is 0.32 x 10^-4

T. Obtain the magnitude of the force on the electron. ​

Answer 1

Answer:

1.024×10^-17 Wb/m^2

Explanation:

See the attachment