Question

An electron is moving with a velocity of 2.5*10^6m/s.if the uncertainity in its velocity is 0.1%,calculate the uncertainity in its position

Answer 1

Answer:

uncertainity in position=2.3×10^-8(approx.)

Explanation:

∆x=h/4πm∆v.....and∆v=0.1%2.5×10^6=0.25×104

∆x=6.626×10^-3/4×3.14×9.1×10^-31×0.25×10^4

=6.626×10^-34/28.574×10^-27

=0.231×10^-7

2.3×10^-8m