Question

An electron is moving with a velocity of 2.56×10^7 m/s. Calculate the minimum uncertainty in the position of an electron

Answer 1

is the velocity given is with uncertainity or is there any percentage of unsertainity given about the velocity. Because if the uncertainity in velocity will be zero

ie delta V then deltaX will tend to infinity.

so i am solving it considering that the velocity given is with uncertainity

The relation we get as given by Heisenberg ie

Delta X × Delta V = h/4pie

So just solve it by taking delta V on the other side and you will be the uncertainitt in the position i hope it will help you