Chemistry, asked by pushkardbg145, 11 months ago

An electron is moving with a velocity of 40m/s, if the uncertainity in its velocity is 0.01% . what will be the uncertainity in its position.

Answers

Answered by mridumoloy
0

Answer:

1.45x10^-68

Explanation:

Mass of electron = 9.1 X 10-31 kg.

uncertainty in position = Planck’s constant / 4 * pi * mass * uncertainty in velocity.

Planck's constant is given the symbol h in physics and numerically is equal to 6.63 x 10^-34 Joule seconds.

So, uncertainty =6.63x10^-34/4x3.14x9.1x10^-31x 40x0.9999

=6.63x10^-65/4x3.14x9.1x39.996

=0.001450327x10^-6

5=1.45x10^-68

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