Question

An electron is moving with velocity v has momentum 3×10^-26 kg.m/s. The de Broglie wavelength associated with it is:
Value of h=6.63×10^-34 Js.
A. 24.1 nm
B. 22.1 micrometer
C. 22.1 nm
D. 22.1 mm

Right answer is C.

Data: P=3×10^-26 kg.m/s, λ=?, h=6.63×10^-34 Js
Solution: λ=h/mv
λ=6.63×10^-34/3×10^-26
λ=2.21×10^-34×10^26
λ=2.21×10^-8m
λ=2.21×10^-8 ×10^9 nm
λ=2.21×10^1 nm
λ=22.1 nm.
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Answer 1

Answer:

Data: P=3×10^-26 kg.m/s, λ=?, h=6.63×10^-34 Js

Solution: λ=h/mv

λ=6.63×10^-34/3×10^-26

λ=2.21×10^-34×10^26

λ=2.21×10^-8m

λ=2.21×10^-8 ×10^9 nm

λ=2.21×10^1 nm

λ=22.1 nm.

aaaa.....u could directly say that it was a free point .

by the way , thanks for the information

Answer 2

Answer:

l don't know the answer sorry ever