Question

An electron is orbiting in 4th bohr orbit Find the ionization energy for this atom if the ground state energy is 13.6 ev​

Answer 1

Answer:

hydrogen

Explanation:

Energy of H-atom in ground state is -13.6eV

Answer 2

The Ionization energy for this atom is 0.85 eV.

Energy of an electron in an orbital of a atom = 13.6 ×( n ²/ z²) eV

n = the orbital number

Z= the atomic number of the atom

For ground state n= 1,

E = 13.6 × z²

Given , E = 13.6 eV

Therefore , the value of Z= 1 and the atom is a hydrogen atom.

Now, Ionization energy for n = 4 and z= 1

I.E = 13.6 × 1/16

=> 0.85 eV