Question

An electron is placed in an electric field of intensity 1000N/C Calculate the force acting on the electron

Answer 1

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Answer 2

Given,

Electric field intensity= 1000 N/C  

To find,

The force acting on the electron

Solution,  

We can simply solve this numerical problem by using the subsequent process  

Now,

Electric field Intensity (E) = 1000 N/C

Charge of electron (qe) = -1.602×10⁻¹⁹C

Force (F) = ?

As we know that,  

F = qeE

where,  

F = Force, qe= Charge of electron, & E = Electric field

F = 1000 N/C × (-1.602×10⁻¹⁹) C

F = -1.602×10⁻¹⁶ N

Hence, the force acting on the electron is -1.602×10⁻¹⁶ N