Question

An electron is present in 3d subshells give the value of its 4 quantum numbers

Answer 1

Explanation:

Correct option is

A

5

Let the atomic number of the atom be Z.

The energy of nth orbit is given as 54.4 eV

∴54.4eV=13.6×

n

2

Z

2

eV⟹Z=2n

Also the frequency of revolution of the electron in nth orbit, ν

n

=6.6×10

15

n

3

Z

2

∴13.2×10

15

=6.6×10

15

n

3

4n

2

⟹n=2

Time taken by the electron to jump from nth orbit to

2

n

th orbit, Δt=7 ns

The change in angular momentum of the electron due to the transition,

ΔL=

2π

nh

−

2π

(

2

n

)h

=

4π

nh

∴ Average torque acted, τ=

Δt

ΔL

=

4×3.14×7×10

−9

2×6.63×10

−34

=15×10

−27

Nm

Answer 2

Answer:

Now they can take any one of the spin quantum number ms={12,−12} . Hence, the set of quantum numbers for electrons in 3d orbital is n=3 , l=2 , ml={−2,−1,0,1,2} and ms={12,−12} .