Question

an electron is released between two points A and B such that Va=-20v,Vb=-40v what is the kinetic energy to point B (e=1.6×10 power-19) (me=9×10 power -31)​

Answer 1

Heya,

Thanks for the question

CONCEPT TO BE USED

Change in kinetic energy = work done.

and, work done = Change in potential energy = q∆V

Thus,

Change in kinetic energy = q∆V.............(1)

Since, initial velocity is 0. Initial K.E. is zero.

So, eq....(I) becomes

K.E. = e∆V

=> K.E. = 1.6 × 10^-19 × (40-20)

= 20 eV. Ans.

Regards

Kshitij