An electron is released from rest on the axis of a uniform positively charged ring at a large distance from the centre will
Answers
It will do oscillatory motion ...but not SHM....i will explain this more simply..
ie ,if the electron is released , it willmoves toward the ring due to attraction since the electron is -ve and ring is +ve
And when it reaches the centre the force become zero and moves away from the ring with decreasing force ...at a moment it gets stopped and moves back to the centre of the ring due to the above explained attractional force between them ..hence they experience oscillatory motion..
I hope u get me..thank you
ANSWER:
When an electron is released along the axis of a positively charged ring, it will experience attraction force, and accelerate towards the ring. When it reaches the centre of the ring, force on it will be zero, but it still has some velocity, so it will continue motion in the same direction. However, now the attraction force from the ring is in the direction opposite to its velocity, so it will decelerate and stop momentarily at some point. Then again it will start moving towards the ring, pass the ring, move away from it and then stop momentarily.
When an electron is released along the axis of a positively charged ring, it will experience attraction force, and accelerate towards the ring. When it reaches the centre of the ring, force on it will be zero, but it still has some velocity, so it will continue motion in the same direction. However, now the attraction force from the ring is in the direction opposite to its velocity, so it will decelerate and stop momentarily at some point. Then again it will start moving towards the ring, pass the ring, move away from it and then stop momentarily.The electron will continue to move this way, and hence we can say that it will execute oscillatory motion.
When an electron is released along the axis of a positively charged ring, it will experience attraction force, and accelerate towards the ring. When it reaches the centre of the ring, force on it will be zero, but it still has some velocity, so it will continue motion in the same direction. However, now the attraction force from the ring is in the direction opposite to its velocity, so it will decelerate and stop momentarily at some point. Then again it will start moving towards the ring, pass the ring, move away from it and then stop momentarily.The electron will continue to move this way, and hence we can say that it will execute oscillatory motion.Now, an oscillatory motion is SHM if and only if F=-kx.
When an electron is released along the axis of a positively charged ring, it will experience attraction force, and accelerate towards the ring. When it reaches the centre of the ring, force on it will be zero, but it still has some velocity, so it will continue motion in the same direction. However, now the attraction force from the ring is in the direction opposite to its velocity, so it will decelerate and stop momentarily at some point. Then again it will start moving towards the ring, pass the ring, move away from it and then stop momentarily.The electron will continue to move this way, and hence we can say that it will execute oscillatory motion.Now, an oscillatory motion is SHM if and only if F=-kx.Here, F= -kQex/(R^2+x^2)^(3/2), where Q = total positive charge on ring, e= charge on electron, x=distance of electron from centre of the ring, R=radius of the ring. (I have used the formula for electric field along the axis of a uniformly charged ring). Hence, in general, we can say that the motion is not SHM. Also, if distance is very large from ring, ie, x>>R, then R^2+x^2 ~ x^2, and we an say F=-kQe/x^2.
x^2, and we an say F=-kQe/x^2.However if the distance of electron from ring was very small, ie, x<<R, then R^2+x^2~R^2, and F=-kQex/R^3. Here, F = -kx, and hence motion is SHM.
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