Question

an electron is sent in an electric field of intensity 9.1 into 10 raise to 6 Newton per coulomb the acceleration produced is​

Answer 1

Answer:

a = 9.1 × 10 raised to the power 6 m/second square.

Explanation :

Answer 2

The acceleration produced by the electron is $1.6\times 10^{18}\ m/s^2$.

Explanation:

It is given that,

Electric field intensity of the electron, $E=9.1\times 10^6\ N/C$

We know that, charge on electron, $q=1.6\times 10^{-19}\ C$

The force acting on the electron in the electric field is given by :

$F=qE$

Also, F = ma

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 9.1\times 10^6}{9.1\times 10^{-31}}$

$a=1.6\times 10^{18}\ m/s^2$

So, the acceleration produced by the electron is $1.6\times 10^{18}\ m/s^2$. Hence, this is the required solution.

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Electric field

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