An electron is to be accelerated in a uniform electric field having a strength of
200 x 10" V/m. What energy in KeV is given to the electron if it is accelerated
0.400 m.tiker = 10'ev]
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Dear Student,
◆ Answer -
Energy required = 0.8 KeV
◆ Explaination -
# Given -
Ex = 200×10 = 2×10^3 V/m
l = 0.4 m
# Solution -
Energy given to electron to accelerate it is given by -
Energy = Electric field strength × charge × distance
E = Ex.e.l
We want our answer in eV so,
E' = Ex.e.l/e
E' = Ex.l
E' = 2×10^3 × 0.4
E' = 800 eV
E' = 0.8 KeV
Therefore, 0.8 KeV energy is to be given to electron for acceleration.
Thanks buddy...
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