Question

an electron is traveling at a speed of 0.2 of speed of light calculate debrongile's wavelength associated with it​
hint:- we have to fill value of light

Answer 1

Explanation:

debroglie wavelength is given by,

$lambda = \frac{h}{mv}$

where,

• h=6.626×10^-34(Planck's constant)
• m=9.1×10^-31kg(mass of electron)
• v=0.2×(3×10^8)

therefore,

lambda(x) is given by,

$x = \frac{6.626× {10}^{ - 34} }{9.1 \times {10}^{ - 31} \times 0.2 \times (3 \times {10}^{8} ) } \\ = 1.2 \times {10}^{ - 11} m$