Question

An electron joins a bare helium nucleus to form a helium positive ion find wavelength of photon emitted if electron had no kinetic energy when combined with nucleus

Answer 1

Answer:

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Explanation:

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Answer 2

Given that,

An electron joins a bare helium nucleus to form a helium positive ion.

If electron had no kinetic energy when combined with nucleus.

$K.E_{i}=0$

We know that,

The atomic number of helium is 2.

The energy of electron is

$E=-13.6\times z^2\ eV$

Put the value of z into the formula

$E=-13.6\times4$

$E=-54.4\ eV$

We need to calculate the wavelength of photon

Using formula of Bohr's model

$\lambda=\dfrac{hc}{\Delta E}$

Put the value into the formula

$\lambda=\dfrac{4.14\times10^{-23}\times3\times10^{8}}{54.4}$

$\lambda= 22.8\times10^{-9}\ m$

$\lambda=22.8\ nm$

Hence, The wavelength of photon is 22.8 nm.