Question

an electron jumps From 3 rd orbit to 1 st orbit calculat the wave length​

Answer 1

Explanation:

The energy of the photon emitted shall equal to the difference between the electron's potential energy at the two orbits.

The Rydberg Formula−−−−−−−−−−−−−−− suggests that an electron that travels (or literally "falls") from energy level ni to nf (ni>nf) emits a photon of wavelength λ for which

1λ=R(1n2f−1n2i)

where the Rydberg's Constant R=1.097×107lm−1.

In this particular scenario

ni=3

nf=1

Such that

Such that

1λ=R(1n2f−1n2i).

Such that

1λ=R(1n2f−1n2i)

ΔPE=1.097×107lm−1⋅(112−132)

ΔPE=9.751⋅107lm−1

λ=1.026×10−7lm⋅109lnm1lm

λ=102.6lnm

References

"Bohr's Hydrogen Atom" , Chemistry Libretext

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