Question

An electron jumps from 5th shell to 2nd shell. How many state of transition are possible.

Answer 1

Consider an electron jumps from 5th shell to 2nd shell.

Then,

N2 = higher energy shell where the electron transitions occur

N1 = lower energy shell

We know the formula, $\frac { \left( N2-N1 \right) \times \left( N2-N1+1 \right)}{ 2 }$

Here, N2 = 5; and N1 = 2;

$=\quad \frac { \left( 5-2 \right) \times \left( 5-2+1 \right) }{ 2 } =\frac { 3\times 4 }{ 2}$

= 6

The number of transitions possible are 6.

Answer 2

Consider an electron jumps from 5th shell to 2nd shell.

Then,

N2 = higher energy shell where the electron transitions occur

N1 = lower energy shell

We know the formula, \frac { \left( N2-N1 \right) \times \left( N2-N1+1 \right)}{ 2 }2(N2−N1)×(N2−N1+1)​

Here, N2 = 5; and N1 = 2;

=\quad \frac { \left( 5-2 \right) \times \left( 5-2+1 \right) }{ 2 } =\frac { 3\times 4 }{ 2}=2(5−2)×(5−2+1)​=23×4​

= 6

The number of transitions possible are6.