An electron jumps in an atom in such a way that its kinetic energy changes from the change in potential energy will be :
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Hello user.
The change in kinetic energy will be
KE =h (v - v0)
The change in kinetic energy will be
KE =h (v - v0)
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Answer: Here is your answer↓
+ 3x /2
Explanation:
change in K.E.(ΔK.E.) = K.E. final ( K.E. f ) - K.E. initial ( K.E. i )
Δ K.E. = X/4 -X
= - 3X/4
Now, we know that Δ K.E. = - ( Δ P.E. /2 )
-3x /4 = Δ P.E. /2
Δ P.E. =3X /2
Therefore ,the change in potential energy will be Δ P.E. =3X /2
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