An electron moves at 2×10^2 m/sec perpendicular to magnetic field of 2t what is the magnetic of magnetic field
Answers
Answered by
15
Answer:6.4×10^-17 N
Explanation:
Force experienced by a change particle is given by =qvBsin(theta)
F=1.6×10^-19×2×10^2×2
F=6.4×10^-17 N
Answered by
10
Answer:
F = 6.4×10^17.
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