An electron moves from point P at potential 30V to point Q such that work done is 1.6*10^-18.Find the potential at point Q
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W = q∆V
W(given) = 1.6*10^-18
∆Vpq = (Vp - Vq) = (30- Vq)
1.6*10^-18 = e(30-Vq)
1.6*10^-18/e = (30-Vq)
-1= 30- Vq
Vq = 31 V
Answered by
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Given:
The potential at point P Vp= 30 V
The work done is W= 1.6×10⁻¹⁸
To find:
The potential at point Q.
Solution:
The formula of work done
The change of potential energy
W= Vp - Vq
1.6×10⁻¹⁸=30 - Vq
Vq= 30- 0.016
Vq=29.984 eV
So the potential at point Q in the form of electron volt is Vq=29.984 eV
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