Question

An electron moves in a circular orbit of radius o.51A° around a nucleus at a frequency of 6.8×10^15 Hz. Estimate the magnetic field at the nucleus.. plz solve this with proper explanations

Answer 1

Explanation:

Given An electron moves in a circular orbit of radius o.51 A° around a nucleus at a frequency of 6.8×10^15 Hz. Estimate the magnetic field at the nucleus.. plz solve this with proper explanations

•   Given radius of   circular orbit r = 0.51 A = 0.51 x 10^-10 m
•    Frequency of the electron f = 6.8 x 10^15 hz
•   Frequency with which an electron moves in the magnetic field is           given by
•    So f = q B / 2 π m , m and q are the mass and charge on proton
•    B = 2 π r n f / q
•      = 2 π x 9.1 x 10^-31 x 6.8 x 10^15 / 1.6 x 10^-19
• B = 2.43 x 10^5 T

Therefore the magnetic field at the nucleus is 2.43 x 10^5 T.  

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