Question

An electron moves in a circular path of radius 20 cm in a uniform magnetic field 2×10^-3 T.Find the speed of the electron and period of revolution.(me=9.1*10^-31 kg)

Answer 1

Answer:

An electron travels in a circular path of radius 20cm in a magnetic field ...

An electron travels in a circular path of radius 20cm in a magnetic field 2×10-3T (i) Calculate the speed of the electron (ii) What ...

Explanation:

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Answer 2

Explanation:

Given :   q=1.6×10−19 C        m=9.1×10−27 kg        v=106 m/s           r=0.5 m

Radius of circular path    r=qBmv

Or    0.5=1.6×10−19×B9.1×10−31×106

⟹ B=11.375×10−6 T=11.375 μT