Question

an electron moves in an orbit of radius 5x 10^-4 with a speed of 2.2x 10^6 m/s . calucate the electric current is​

Answer 1

Answer:

Explanation:

r=5×10  

−11

 

v=2.2×10  

6

m/s

time period,

T=  

v

2πr

​

 

current = charge passing per unit time

I=  

t

q

​

 

t=  

v

2πr

​

 

I=  

2πr

q

​

.v

=  

5×10  

−11

×2π

1.6×10  

−19

×2.2×10  

6

 

​

 

=  

5×2π

1.6×2.2

​

×10  

−2

 

=1.12×10  

−3

A

I=1.12mA