an electron moves in circular path of radius 15 CM in magnectic field 4g find it's velocity
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1
Answer:
Correct option is
A
2.0×10
−24
kg
R
mv
2
=qvB
mv=qBR
Path is straight line
it qE = qvB
E = vB
From equation (i) & (ii)
m=
E
qB
2
R
m=2.0×10
−24
kg
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