Question

An electron moving perpendicular to a uniform magnetic field 0.500T undergo circular motion of radius 2.80MM what is the speed of electron

Answer 1

Explanation:

Given An electron moving perpendicular to a uniform magnetic field 0.500 T undergo circular motion of radius 2.80 MM what is the speed of electron

• So charge of an electron q = - 1.6 x 10^- 19 C
• So l q l = 1.6 x 10^-19 C
• Magnitude of magnetic field B = 0.500 T
• Mass of  electron will be m = 9.1 x 10^-31 kg
• Radius will be r = 2.50 mm = 2.5 x 10^-3 m
• Now velocity of the electron v = l q l r B / m
• Or v = 1.6 x 10^-19 x 2.5 x 10^-3 x 0.500 / 9.1 x 10^- 31
• Or v = 2.195 x 10^8 m / s

Reference link will be

https://brainly.in/question/14430108

Answer 2

The speed of electron is 2.46 × 10⁸ m/s

Given:

Magnetic field = B = 0.500 T

Radius of circular motion = r = 2.80 mm

Explanation:

The force acting on the electron due to magnetic field is given as:

F = qvB = mv²/r

v = rqB/m

Where,

q = Charge of electron = 1.6 × 10⁻¹⁹ C

m = Mass of electron = m = 9.1 × 10⁻³¹ kg

On substituting the values, we get,

v = (0.0028 × 1.6 × 10⁻¹⁹ × 0.5)/(9.1 × 10⁻³¹)

∴ v = 2.46 × 10⁸ m/s